Consider the circuit shown in figure (32-E19a). Find (a) the current in the circuit, (b) the potential drop across the 5Ω resistor, (c) the potential drop across the 10Ω resistor. (d) Answer the parts (a), (b) and (c) with reference to figure (32-E19b)
(a)ApplyingKirchoff's law,
⇒10i−6+5i−12=0
⇒10i+5i=18
⇒15i=18
i=1815=65=1.2 A
(b)Potential drop across 5 Ω register,
i5=1.2×5V=6V
(c)Potential drop across 10Ω register,
i10=1.2×10V=12V
(d) 10i+5i−6−12=0
⇒15i=18
⇒i=1.2
Potential drop across 5Ω register,
=6V Potential drop across 10Ω register,
=12 V