Question

Consider the circuit shown in th figure.

The Thevenin equivalent resistance (in $\Omega$) across P-Q is

• A. -1

Answer 1

The correct option is A -1

• The equivalent circuit to calculate the Thevenin equivalent resistance ($R_{Th}$) is as follows:

• It can be further reduced as follows:

• By applying KVL in the loop L,

$V_x=3i_0$ + (1 - $i_0$) = $2i_0+1$

$Also,V_x$ = $i_0$(1$\Omega$)

• $So,2i_0+1=i_0$

$i_0=-1A$

And $V_x=-1V$

$So,R_{Th}=\frac{V_x}{1A}=1\Omega$