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Question

# Consider the circuit shown in the figure below: Assume that the transistor hasβ=99,VA=100V and VT=25mV, then the small-signal voltage gain Av=v0vs is equal to

A
-23.10
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B
-9.74
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C
-19.40
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D
-7.94
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Solution

## The correct option is D -7.94rπ=VTIDC=VTIC=VTαIEα=ββ+1=9999+199100=0.99∴IC=0.99×1.01=0.999mA≈1mA∴rπ=25kΩnow,r0=VAIDC=1001×10−3=100kΩ Thus drawing the small signal equivalent, we get, gmrπ=βgm=βrπ=9925×10−3=4mA/V∴V0=−[(10k∥25k)(10k∥25k)+10k]gm(100k∥5k)VsV0Vs=−(0.417)×(4×10−3)×(4.7619)×10−3Av=−V0Vs=−7.94

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