Question

Consider the circuit shown in the figure below

If the biasing condition of the circuit is met for the circuit to start oscillating, then the frequency of oscillation is equal to ____Hz

• A. 159.15

Answer 1

The correct option is A 159.15

$f=\frac{1}{2\pi \sqrt{L_{eq}C}}$

$L_{eq}=L_1+L_2=10\times {10}^{-3}+10\times {10}^{-3}$

$=20\times {10}^{-3}H$

$C=50\times {10}^{-6}F$

$\therefore f=\frac{{10}^3}{2\pi }=159.15Hz$