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Kirchoff's Junction Law

Consider the ...

Question

Consider the circuit shown in the figure below

If the cut-in voltage of the diode $D_{1}$ is equal to 0.7 V, then the value of current flowing through the diode is

A

3 mA

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B

2 mA

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C

1 mA

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D

0

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Solution

The correct option is D 0
Drawing the Thevenin equvalent circuit, we get

Applying KVL we get $V_{D} = 0 V$ , thus no current will flow through the diode $D_{1}$
Hence I = 0A

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