Question

Consider the circuit shown in the figure below:


If the diode D is ideal, then the transfer characteristic curve of the circuit can be represented as

Answer 1

Case I: When $V_{in}>0$
The diode will conduct, thus the equivalent circuit can be given as,




$\therefore V_{out}-V_{in}$

Case II: when the input voltage $V_{in}<0$. The diode will not conduct, thus the equivalent circut can be given as

$\therefore V_{out}=V_{in}\frac{R}{R+R}=\frac{V_{in}}{2}=0.5V_{in}$