Consider the circuit shown in the figure below.
If the value of emiitter voltage VE is equal to 4V, then the value of current gain β is (Assume|VBE|=0.7V).
A
18
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B
27
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C
11
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D
21
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Solution
The correct option is D21 IE=10−VE4kΩ=10−44kΩ=1.5mA VC=−5+1.5=−3.5V VEB=VE−VB=0.7V VB=4−0.7=3.3V VBC=VB−VC=3.3−(−3.5)=6.8V IB=VBC100kΩ=0.068mA IEIB=β+1 1.50.068=β+1 β=21