Question

Consider the circuit shown in the figure below:

If the value of voltage on the secondary side of tranformer is
$V_m\left(t\right)=V_m\sin \left(\omega t\right)$,

then the value of $V_0$ is equal to

• A. $-V_m$
• B. $0.5V_m$
  
• C. $V_m$
• D. $2V_m$

Answer 1

The correct option is A $-V_m$

The circuit can be redrawn as,

The circuit represents a voltage doubler circuit, if the voltage voltages was taken by adding volltages of both the capacitors, but to calculate $V_0$ we have to find the voltage stored on a single capacitor Thus, comparing from the above figures,
$V_0=-V_m$