Question

Consider the circuit shown in the figure below:

$\text{If the value of voltage on the secondary side of transformer is}{V}_m\left(t\right)=V_m\sin \left(\omega t\right)\text{, then the value of}{v}_0\text{is equal to}$

• A. $0.5V_m$
• B. $0.5V_m$
• C. $-V_m$
• D. $V_m$

Answer 1

The correct option is C $-V_m$

The circuit can be redrawn as,

$\text{The circuit represents a voltage doubler circuit, if the voltage was taken by adding voltages of both the capacitors, but to calculate}{V}_0\text{we have to find the voltage stored on a single capacitor. Thus, comparing from the above figure,}$
$V_0=-V_m$