Question

Consider the circuit shown in the figure below;

$\text{the output voltage}{V}_0\text{is equal to\_\_\_\_\_V.}$

• A. -8

Answer 1

The correct option is A -8
$V_0=-80\text{k}\Omega [\frac{2}{20\text{k}\Omega }+\frac{-2}{40\text{k}\Omega }+\frac{3}{60\text{k}\Omega }]=-8V$