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Full Wave Rectifier

Consider the ...

Question

$C o n s i d e r t h e c i r c u i t s h o w n i n t h e f i g u r e b e l o w .$

$T h e t r a n s i s t o r i s b i a s e d s u c h t h a t t h e v a l u e o f g_{m} = 2 m A / V, t h e n t h e v a l u e o f o u t p u t r e s i s t a n c e R_{0} i s e q u a l t o . . . K Ω . [A s s u m e v a l u e o f λ = 0.1 V^{- 1}]$
0.408

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Solution

The correct option is A 0.408
$D r a w i n g t h e s m a l l s i g n a l e q u i v a l e n t m o d e l, w e g e t,$

$A p p l y i n g K C L a t n o d e A, w e g e t, ∴ I = \frac{V}{4 k Ω} + \frac{V}{r_{0}} - g_{m} V_{i n} N o w V_{i n} = - V, I = \frac{V}{4 k Ω} + \frac{V}{r_{0}} + g_{m} V \frac{1}{V} = \frac{1}{4 k Ω} + \frac{1}{r_{0}} + \frac{1}{1 / g_{m}} \frac{V}{1} = R_{o} = 4 k Ω | | r_{o} | | 1 / g_{m} n o w, v a l u e o f r_{o} = \frac{V_{A}}{I_{D}} = \frac{1}{λ I_{D}} = \frac{1}{0.1 \times 2 \times 10^{(} - 3)} = 5 k Ω a n d \frac{1}{8_{m}} = \frac{1}{2 \times 10^{- 3}} = 500 Ω = 0.5 k Ω ∴ R_{o} = 4 k Ω | | 5 k Ω | | 0.5 k Ω R_{o} = 0.408 K Ω .$

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Similar questions

g_{m} = 5 m A / V .

R_{i n}

c o n s i d e r t h e c i r c u i t s h o w n i n t h e f i g u r e b e l o w . t h e v a l u e o f C_{1}, C_{2} a n d C_{c} i s v e r y l a r g e a n d t h e t r a n s i s t o r i s b i a s e d s u c h t h a t t h e v a l u e o f g_{m} = 20 m A / V λ = 0.01 V^{- 1} I f t h e M O S t r a n s i s t o r h a s t h e n t h e v a l u e o f v o l t a g e g a i n \frac{V_{0}}{V_{s}} i s e q u a l t o . . . . . V / V .

I_{c} = 3.94

R_{0}

V_{in}

V_{0}

V_{in}

(Assume, V_{B E (O N)}) = 0.7 V

V_{T} = 1 V

λ = 0

\frac{μ_{n} C_{o x} W}{L} = 2 m A / V^{2}

T_{2} (V_{D S 2})

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