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Full Wave Rectifier

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Question

$c o n s i d e r t h e c i r c u i t s h o w n i n t h e f i g u r e b e l o w . t h e v a l u e o f C_{1}, C_{2} a n d C_{c} i s v e r y l a r g e a n d t h e t r a n s i s t o r i s b i a s e d s u c h t h a t t h e v a l u e o f g_{m} = 20 m A / V λ = 0.01 V^{- 1} I f t h e M O S t r a n s i s t o r h a s t h e n t h e v a l u e o f v o l t a g e g a i n \frac{V_{0}}{V_{s}} i s e q u a l t o . . . . . V / V .$

-181.81

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Solution

The correct option is A -181.81
$r_{0} = \frac{1}{λ I_{D}} n o w, I_{D} = 1 m A ∴ r_{0} = \frac{1}{0.01 \times 10^{- 3}} = 100 k Ω V_{0} = - g_{m} (r_{o} | | R_{D}) V_{s} \frac{v_{0}}{V_{s}} = - 20 \times 10^{- 3} \times [100 k Ω | | 10 k Ω] = - 20 \times 10^{- 3} \times 9.09 \times 10^{3} = - 181.81 V / V .$

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Similar questions

C o n s i d e r t h e c i r c u i t s h o w n i n t h e f i g u r e b e l o w .

T h e t r a n s i s t o r i s b i a s e d s u c h t h a t t h e v a l u e o f g_{m} = 2 m A / V, t h e n t h e v a l u e o f o u t p u t r e s i s t a n c e R_{0} i s e q u a l t o . . . K Ω . [A s s u m e v a l u e o f λ = 0.1 V^{- 1}]

V_{T} = 1 V

λ = 0

\frac{μ_{n} C_{o x} W}{L} = 2 m A / V^{2}

T_{2} (V_{D S 2})

| V_{B E} |

V_{c c} = 12 V .

β = 100

S (I_{c o})

g_{m} = 5 m A / V .

R_{i n}

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