Question

Consider the circuit shown in the figure below:

The Zener diode is an ideal diode with Zener breakdown voltage $V_Z=3.3V$. If the value of output voltage $V_0=3.5V,$ then the current through the zener diode is equal to

• A. 6 mA
• B. 16 mA
• C. 8 mA
• D. 2 mA

Answer 1

The correct option is D 2 mA

$V_0=3.5V$
$\therefore$ Drop across 0.1 k$\Omega$ resistor=$3.5-3.3=0.2V$
$\therefore I_z=\frac{0.2}{0.1}\times {10}^{-3}=2mA$