Consider the circuit shown in the figure below.

Which of the following statement is correct?

Y = 0 f o r A = 0, B = 0 a n d C = 1

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Y = 1 f o r A = 1, B = 0 a n d C = 0

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Y = 1 f o r A = 0, B = 0 a n d C = 1

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Y = 1 f o r A = 1, B = 1 a n d C = 0

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Solution

The correct option is C $Y = 1 f o r A = 0, B = 0 a n d C = 1$
$W h e n A = 0 B = 0 I_{0} = 1$ and remaining are zero.

Output of first $2 \times 1$ MUX is $¯ ¯¯ ¯ C$ .

$Y =_{0} I_{0} + S_{0} I_{1} = C + ¯ C = 1$

Only option C is satisfied.

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