1
Question
Consider the circuit shown in the figure. The current i3 is equal to
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Solution
The correct option is D −56 amp
Suppose current through different paths of the circuit is as follows.
After applying KVL for loop (1) and loop (2)
We get 28i1=−6−8⇒i1=−12A
and 54i2=−6−12⇒i2=−13A
Hence i3=i1+i2=−56A
Suppose current through different paths of the circuit is as follows.
After applying KVL for loop (1) and loop (2)
We get 28i1=−6−8⇒i1=−12A
and 54i2=−6−12⇒i2=−13A
Hence i3=i1+i2=−56A
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