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Question

Consider the circuit shown in the figure. The sliding contact is being pulled towards the right so that the resistance in the circuit is increasing. Its value at the instant shown is 12Ω. The current flowing in the circuit is i. Then :


A
i=0.5 A
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B
None of the above
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C
i>0.5 A
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D
i<0.5 A
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Solution

The correct option is C i>0.5 A
As the sliding contact is being pulled, the current in the circuit changes.

An induced emf, E=Ldidt is produced across the inductor.

The net emf in the circuits is,

Enet=6 VLdidt

And hence the current is,

i=EnetR=6Ldidt12 ...(i) [At the instant shown]


Now the resistance in the circuit is increasing, so the current is decreases and so didt is negative.

Thus, the numerator of (i) is more than 6 and hence i is greater than 612=0.50 A.

Thus, option (B) is the correct answer.

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