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Byju's Answer
Standard XII
Mathematics
Sum of n Terms
Consider the ...
Question
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then the p
ossible difference between the argument of
z
1
and
z
2
is,
A
0
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B
π
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C
−
π
2
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D
none of these
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Solution
The correct option is
C
−
π
2
Given that,
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
⇒
|
z
1
|
2
+
|
z
2
|
2
+
z
1
¯
¯
¯
z
2
+
¯
¯
¯
z
1
z
2
=
|
z
1
|
2
+
|
z
2
|
2
⇒
z
1
¯
¯
¯
z
2
+
¯
¯
¯
z
1
z
2
=
0
⇒
z
1
z
2
+
¯
¯
¯
z
1
¯
¯
¯
z
2
=
0
(divided by
z
2
¯
¯
¯
z
2
)
⇒
z
1
z
2
+
(
¯
¯¯¯¯¯
¯
z
1
z
2
)
=
0
z
1
/
z
2
is purely imaginary.
Hence,
a
r
g
(
z
1
z
2
)
=
±
π
2
Suggest Corrections
0
Similar questions
Q.
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then
one of the possible argument of complex number
i
z
1
z
2
is,
Q.
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then
complex number
z
1
¯
¯
¯
z
2
is,
Q.
If
z
1
&
z
2
are two complex numbers and
a
r
g
(
z
1
+
z
2
z
1
−
z
2
)
=
π
2
but
|
z
1
+
z
2
|
≠
|
z
1
−
z
2
|
, then the figure formed by the points represented by 0,
z
1
,
z
2
,
z
1
+
z
2
is
Q.
If
z
1
,
z
2
are two different complex numbers satisfying
|
z
2
1
−
z
2
2
|
=
|
¯
¯
¯
z
2
1
+
¯
¯
¯
z
2
2
−
2
¯
¯
¯
z
1
¯
¯
¯
z
2
|
,
then
Q.
If |
Z
1
+
Z
2
| = |
Z
1
| - |
Z
2
| where
Z
1
,
Z
2
are two non-zero complex numbers, then arg(
Z
1
) - arg(
Z
2
) is
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