Consider the coordination compound, $[C o (N H_{3})_{6}] C l_{3}$ . In the formation of this complex, the species which acts as the Lewis base is:

C l^{-}

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C o^{3 +}

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N H_{3}

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[C o (N H_{3})_{6}]^{3 +}

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Solution

The correct option is D $N H_{3}$
A Lewis base is any species that donates a pair of electrons to a Lewis acid to form a Lewis adduct.
For example, $O H^{-}$ and $N H_{3}$ are Lewis bases, because they can donate a lone pair of electrons.
Here, $N H_{3}$ has lone pairs on it which it can donate.

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Similar questions

Q. The oxidation state of cobalt in the complex compound

[C o (N H_{3})_{6}] C l_{3}

Q. Coordination number of

C o

[C o {({N H}_{3})}_{6}] {C l}_{3}

is:

Q. Among the following, which complex compound is diamagnetic?

[C o (N H_{3})_{6}] C l_{3}

,
ii)

[N i (N H_{3})_{6}] C l_{2}

,
iii)

[C r (H_{2} O)_{6}] C l_{3}

,
iv)

[F e (H_{2} O)_{6}] C l_{2}

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

Q. The correct increasing order of wavelengths of absorption in the visible region for the complexes of

C o^{3 +}

is:

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Consider the coordination compound, [Co(NH3)6]Cl3. In the formation of this complex, the species which acts as the Lewis base is:

The correct option is D NH3A Lewis base is any species that donates a pair of electrons to a Lewis acid to form a Lewis adduct. For example, OH− and NH3 are Lewis bases, because they can donate a lone pair of electrons.Here, NH3 has lone pairs on it which it can donate.

Consider the coordination compound, $[C o (N H_{3})_{6}] C l_{3}$ . In the formation of this complex, the species which acts as the Lewis base is:

The correct option is D $N H_{3}$
A Lewis base is any species that donates a pair of electrons to a Lewis acid to form a Lewis adduct.
For example, $O H^{-}$ and $N H_{3}$ are Lewis bases, because they can donate a lone pair of electrons.
Here, $N H_{3}$ has lone pairs on it which it can donate.