Question

Consider the coordination compound, $N{a}_2\left[Pt\right(CN{)}_4]$. The lewis base is

• A. $\left[Pt\right(CN{)}_4{]}^{2-}$
• B. $N{a}^{+}$
• C. $P{t}^{2+}$
• D. $C{N}^{-}$

Answer 1

The correct option is D $C{N}^{-}$

In general, ligands will donate the electron to central metal atom in coordination complex and behave as lewis base.
In $N{a}_2\left[Pt\right(CN{)}_4]$, the ligand is $C{N}^{-}$. Hence, $C{N}^{-}$ is lewis base.