Question

Consider the cyclic process ABCA, shown in figure, performed on a sample of 2.0 mole of an ideal gas. A total of 1200 j of heat is withdrawn from the sample in the process. Find the work done by the gas during the part BC.

Answer 1

$n=2$mole

$dQ=-1200J$

$dU=0$ (During cyclic Process)

$dQ=dU+dwc$

$\Rightarrow -1200=W_{AB}+W_{BC}+W_{CA}$

$\Rightarrow -1200=nR\Delta T+W_{BC}+0$

$\Rightarrow -1200=2\times 8.3\times 200+W_{BC}$

$\Rightarrow W_{BC}=-400\times 8.3-12100=-4520J$