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Question

Consider the differential equation:
(1+(dydx)2)32d2ydx2=c.
Find order and degree.

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Solution

Given the differential equation,
(1+(dydx)2)32d2ydx2=c
or, (1+(dydx)2)32=cd2ydx2
or, (1+(dydx)2)3=c2(d2ydx2)2.
From the above equation it quite clear that the order of the differential equation is 2 and degree is also 2.

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