Question

Consider the differential equation $\frac{dy}{dx}=\cos x$ Then we observe that

• A. $y=\sin x$
• B. $y=\sin x+2$
• C. $y=\sin x-\frac{1}{2}$
• D. $y=\sin x+c$

Answer 1

The correct option is D $y=\sin x+c$

$dy=\cos xdx\int dy=\int \cos xdxy=\sin x+C$

We must add constant "C" as its family of curves.