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Question

Consider the differential equation x2d2ydx2+xdydx−y=0. Which of the following is a solution to this differential equation for x>0 ?

A
ex
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B
x2
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C
1/x
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D
lnx
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Solution

The correct option is C 1/x
It is Homogeneous Linear D.E. of 2nd order
x2d2ydx2+xdydxy=0
Let z=logx
A.E. is D(D1)+D1=0
D21=0
D=±1
y=C1ez+C2ez
y=C1x+C2x
y=x,y=1x are the solution of the given differential equation.

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