Consider the diode circuit shown in the figure below.

$The diodes are identical with cut-in voltage 0.6 V then the current flowing through diode D_{2} is equal to ______mA .$
7.6

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Solution

The correct option is A 7.6

$Assume that diode D_{3} is ON, then we find that voltage V_{1} will be equal to 5 - 0.6 = 4.4 V .$

$now, if V_{1} = 4.4 V then diode D_{1} will be OFF .$

$∴ Current through diode D_{2} is equal to I_{D 2} = \frac{4.4 - 0.6}{0.5} \times 10^{- 3} = 7.6 mA$

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