Consider the electric field $\to E = E_{0}^x$ , where $E_{0}$ is a constant. The flux through the shaded area shown in the figure due to this field is,

2 E_{0} a^{2}

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E_{0} a^{2}

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\frac{E_{0} a^{2}}{\sqrt{2}}

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\sqrt{2} E_{0} a^{2}

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Solution

The correct option is B $E_{0} a^{2}$
As we know that,
$Flux = (Field) (projected area)$
Here, projected area towards $x -$ axis is $a^{2}$ and electric field is $\to E = E_{0}^x$
So, flux $ϕ = E_{0} a^{2}$

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Consider the electric field →E=E0^x, where E0 is a constant. The flux through the shaded area shown in the figure due to this field is,

The correct option is B E0a2As we know that, Flux=(Field)(projected area) Here, projected area towards x−axis is a2 and electric field is →E=E0^x So, flux ϕ=E0a2

Consider the electric field $\to E = E_{0}^x$ , where $E_{0}$ is a constant. The flux through the shaded area shown in the figure due to this field is,

The correct option is B $E_{0} a^{2}$
As we know that,
$Flux = (Field) (projected area)$
Here, projected area towards $x -$ axis is $a^{2}$ and electric field is $\to E = E_{0}^x$
So, flux $ϕ = E_{0} a^{2}$