Consider the elements present in the given box- Ca- O- Cl- Na- Mg- C- -The total number of elements that forms divalent cation is

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Valency

Consider the ...

Question

Consider the elements present in the given box.

$\begin{matrix} Ca, O, Cl, Na, Mg, C \end{matrix}$

The total number of element(s) that form(s) divalent cation is

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\begin{matrix} C l^{-}, A r, K^{+}, O^{2 -}, M g^{2 +}, F^{-} \end{matrix}

C a^{2 +}

[N a^{+}] = 56 m g / L; [C a^{2 +}] = 40 m g / L;

[M g^{2 +}] = 30 m g / L; [A l^{3 +}] = 3 m g / L;

[H C O_{3}^{-}] = 190 m g / L; [C l^{-}] = 165 m g / L;

C a = 40, M g = 24, A l = 27, H = 1, C = 12, O = 16, N a = 23, C l = 35.5

C a C O_{3}

p H = 8.10

Ion	$C a^{2 +}$	$M g^{2 +}$	$N a^{+}$	$H C O_{3}^{-}$	$S O_{4}^{2 -}$	$C l^{-}$
Ion concentration $(m g / L)$	$100$	$6$	$15$	$250$	$45$	$39$
Atomic weight	$C a = 40$	$M g = 24$	$N a = 23$	$H = 1$ $C = 12$ $O = 16$	$S = 32$ $O = 16$	$C l = 35.5$

(m g / L a s C a C O_{3})

\begin{matrix} C o l u m n - I & C o l u m n - I I (a) & B e & (p) & S h o w d i a g o n a l r e l s t i o n s h i p w i t h o t h e r e l e m e n t s (b) & M g & (q) & H i g h e s t h y d r a t i o n e n e r g y o f c a t i o n a m o n g t h e e l e m e n t s (c) & C a & (r) & C a t i o n h a s l o w e s t h y d r a t e d s i z e i n a q u e o u s s o l u t i o n (d) & S r & (s) & M e t a l (s) w h i c h d i s s o l v e i n l i q u i d a m m o n i a t o g i v e d e e p b l u e s o l u t i o n (t) & s - b l o c k e l e m e n t s \end{matrix}

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