Question

Consider the equation of curve $y=x^2-3x+3$ and $x\ne 3.$
Then number of critical point(s) for given curve is

[2 marks]

• A. $3$
• B. $2$
• C. $0$
• D. $1$

Answer 1

The correct option is D $1$

$y=x^2-3x+3$
$\Rightarrow \frac{dy}{dx}=2x-3$
For critical points : $\frac{dy}{dx}=0$
$\Rightarrow 2x-3=0$
$\Rightarrow x=\frac{3}{2}$
Hence, there is only one critical point.