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Question

Consider the equation x2+2xn=0, where n[5,100]. Total number of different values of n so that the given equation has integral roots is:


A

4

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B

3

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C

6

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D

8

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Solution

The correct option is D

8


The roots of the equation are:
2±44(n)2
=2±4(1+n)2
=2±21+n2
=1±1+n

It will be an integer when 1+n is a perfect square. Given n[5,100], 1+n will be a perfect square when1+n=9,16,25,36,49,64,81,100n=8,15,24,35,.......99
Number of different values of n is 8.


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