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Question

Consider the equation x22xn=0, where nN and n[5,100]. The total number of different values of n so that the given equation has integral roots is

A
8
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B
3
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C
6
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D
4
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Solution

The correct option is A 8
Given x22xn=0

The given equation has integral roots.

The sum of the roots =2

Let the roots be 1k,k+1 , where k is a positive integer.

Product of the roots =1k2=n

k21=n

n[5,100]

5n100

6n+1101

6k2101

k2=9,16,25,36,64,49,64,81,100

For k=3,4,5,6,7,8,9,10

Hence, there will be 8 corresponding values of n.

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