Give equation, x9+5x8−x3+7x+2=0, has two changes of signs. Hence there can be a maximum of 2 positive roots.
f(−x)=−x9+5x8+x3−7x+2=0, which has three changes of signs. Hence the given equation has a maximum of 3 negative roots.
Now, as the equation is of 9th degree, it must have at least (9−2−3)=4 imaginary roots.