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Question

Consider the equation x9+5x8x3+7x+2=0. Find the number of imaginary roots.

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Solution

Give equation, x9+5x8x3+7x+2=0, has two changes of signs. Hence there can be a maximum of 2 positive roots.

f(x)=x9+5x8+x37x+2=0, which has three changes of signs. Hence the given equation has a maximum of 3 negative roots.

Now, as the equation is of 9th degree, it must have at least (923)=4 imaginary roots.


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