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Common Ion Effect

Consider the ...

Question

Consider the equilibrium:
$H g O (s) + 4 I^{-} (a q) + H_{2} O (l) ⇌ H g I_{4}^{2 -} (a q) + 20 H^{-} (a q)$
Which changes will decrease the equilibrium concentration of $H g I_{4}^{2 -}$ ?

Addition of

0.1 M

H I

(aq.)

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Addition of

H g O

(s)

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Addition of

H_{2} O

(l)

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Addition of

K O H

(aq.)

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Solution

The correct options are
C Addition of $H_{2} O$ (l)
D Addition of $K O H$ (aq.)
Addition of water will result in dilution. It will decrease the concentration of all the species.
Addition of hydroxide ion will shift the equilibrium to left so that more and more hydroxide ions will react to nullify the effect of increased hydroxide ion concentration.
In both these cases, the equilibrium concentration of $H g l_{4}^{2 -}$ will decrease.

Suggest Corrections

Similar questions

Δ H < 0

H g O (s) + 4 I^{-} (a q .) + H_{2} O (l) ⇌ {H g I_{4}}^{2 -} + 2 {O H}^{-}

{H g I_{4}}^{2 -}

I

H g O (s)

I I

[I^{-}]

I I I

1 M

H C l

H C N (a q) ⇌ H^{+} (a q) + C N^{-} (a q)

C N^{-} (a q)

H g O

H g O

H_{2} O + H g O + 4 I^{-} \to H g I_{4}^{2 -} + 2 O H^{-}

H C N (a q) ⇋ H^{+} (a q) + C N^{-} (a q)

C N^{-}

H C N (a q) ⇌ H^{+} (a q) + C N^{-} (a q)

C N^{-} (a q)

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