Question

Consider the equilibrium system: $2ICl\left(s\right)\rightleftharpoons I_2\left(s\right)+C{l}_2\left(g\right)$
Which of the following changes will increase the total amount of $C{l}_2$ that can be produced?

• A. Removing some of the $I_2\left(s\right)$
• B. Adding more ICl(s)
• C. Removing the $C{l}_2$ as it is formed
• D. Decreasing the volume of the container

Answer 1

The correct option is C Removing the $C{l}_2$ as it is formed

The constituents in solid phase don’t contribute anything to the system at equilibrium.
So, the option a and b are discarded. when we remove the $C{l}_2$ , the concentration of it, i.e. product decreases.
According to Le- Chatilier’s principle decreasing the the product concentration will shift the equilibrium towards right. So, the total amount of $C{l}_2$ increases.
By decreasing the volume the no. of molecules per unit volume increases. Then the equilibrium shifts towards the direction where number of molecules are less, i.e. towards left. So, it will decrease the amount of $C{l}_2$. This option D is also not correct.
So, the correct option is C.