Consider the expansion of (x+y)20. 12th term from the end = pth term from the beginning. Find the value of p
10
In the expansion of (a+b)n, there will be (n+1) terms in total.
1st term from the end = (n+1)th term from the beginning
2nd term from the end = (n+1−1)th term from the beginning
Similarly, qth term from the end =(n+1−(q−1))th term from the beginning
⇒12th term from the end =(n+1−(12−1))th term from the beginning
Here, n=20
⇒(20+1−(12−1))th term = 10th term