Question

Consider the figure below:

If $\Delta BOC\cong \Delta AOD$ , and $\angle$ $ADO={30}^o$, then what is the measure of $\angle BCO$ (in degrees) ?

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Answer 1

Since, $\Delta BOC\cong \Delta AOD$,

Corresponding angles of the triangles are equal. It gives,
$\angle BCO$ = $\angle$ $ADO={30}^o$