Question

Consider the figure. Each capacitor has capacitance C.

The capacitance between 1 and 3 is

• A. $\left(\frac{3C}{4}\right)$
• B. $\left(\frac{3C}{2}\right)$
• C. $\left(\frac{5C}{2}\right)$
• D. $\left(\frac{5C}{4}\right)$

Answer 1

The correct option is C $\left(\frac{5C}{2}\right)$

First of all we need to connect points 1 and 3 to a power source or battery.
Now locate the equi_potential points between 1 and 3. Remove the capacitors in between these equi-potential points as there is no flow of charge in between these points.
The arrangement of capacitors between points 1 and 3 now can be visualized as So, the equivalent capacitance between points 1 and 3 will be
$C_{eq}=C+\frac{3C}{2}$

$⟹C_{eq}=\frac{5C}{2}$