Question

Consider the figure given. Each capacitor has capacitance $C$. The equivalent capacitance between $1$ and $3$ is :

• A. 0
• B. $\frac{3C}{2}$
• C. $\frac{5C}{2}$
• D. $\frac{5C}{4}$

Answer 1

The correct option is C $\frac{5C}{2}$

Here 2,4 and 5 are equipotential points and the equivalent circuit is shown in below.
The equivalent capacitance between 1 and 3 is $C_{13}=\frac{(C+C+C)(C+C+C)}{(C+C+C)+(C+C+C)}+C=\frac{\left(3C\right)\left(3C\right)}{3C+3C}+C=\frac{3C}{2}+C=\frac{5C}{2}$