Consider the figure:
If ∠A=50∘, ∠B=70∘, and x=2y, then find the value of x+2y.
160∘
x+y=∠A+∠B
[By exterior angle property]
=50o+70o=120∘
Also given,
x=2y
Thus,
x+y=120∘⇒2y+y=120o⇒3y=120o⇒y=120o3⇒y=40∘
Hence,
x=2y =40o×2 =80∘
∴x+2y=80o+80o=160o
So, the value of
x+2y=160∘