Consider the figure:
If ∠A = 50∘, ∠B = 70∘, and x = 2y, then find the value of x + y+ ∠ACB.
x + y = ∠A+∠B (exterior angle property) = 120∘ also, x = 2y thus, 3y = 120∘ or y = 40∘ Hence, x = 80∘
x + y +∠ACB = 180∘
If ∠A=50∘, ∠B=70∘, and x=2y, then find the value of x+2y.
If ∠A = 50∘, ∠B = 70∘, and x = 2y, then find the value of y (in degrees).
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If BC = AC, x = 2y, and ∠ACB = 60o, then find the value of ∠A + ∠B + x + y (in degrees).
If BC = AC, x = 2y, and angle ACB = 60o, then find the value of ∠A + ∠B + ∠x + ∠y (in degrees).
If ∠A = 50∘, ∠B = 70∘, and x = 2y, then, the value of x (in degrees) is___.