- B -50- - ACD -120- then the value of - A in degrees is-

By Exterior Angle property, ∠ACD = ∠A + ∠B ∴ ∠A = ∠ACD ∠B = 120^∘ 50^∘ = 70^∘ ...

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Exterior Angle of a Triangle and Its Property

∠ B =50∘, ∠ A...

Question

Consider the figure:

If $∠$ B = $50^{\circ}$ , $∠$ ACD = $120^{\circ}$ , then the value of $∠$ A (in degrees) is .

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