Consider the figure-If BC - AC - x -2 y- and angle - ACB -60- then find the value of - x - y in degrees- 100 - y -80- x -40D- y -40

The correct options are A 100 D y=40 ∠C = 60^∘ and BC = AC, By angle sum property of triangle, ∠A = ∠B = 60^∘ ∠A + ∠B + x + y = 60^∘ + 60^∘ + 120^∘ = 240 ...

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Standard VI

Mathematics

Exterior Angle Property

Consider the ...

Question

Consider the figure:

If BC = AC, x = 2y, and angle ∠ACB = 60^o, then find the value of ∠x & ∠y (in degrees).

100

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y = 80

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x = 40

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y = 40

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Solution

The correct options are
A
100

D $y = 40$

$∠$ C = $60^{\circ}$ and BC = AC,
By angle sum property of triangle, $∠$ A = $∠$ B = $60^{\circ}$

$∠$ A + $∠$ B + x + y = $60^{\circ}$ + $60^{\circ}$ + $120^{\circ}$ = $240^{\circ}$
=>y + 2y = $120^{\circ}$ => $y = 40^{\circ}$

Hence, $x = 2 y = 2 \times 40$
$∴ x = 80$

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Consider the figure: If BC = AC, x = 2y, and angle ∠ACB = 60o, then find the value of ∠x & ∠y (in degrees).

The correct options are A 100 D y=40 ∠C = 60∘​ and BC = AC, By angle sum property of triangle, ∠A = ∠B = 60∘​ ∠A + ∠B + x + y = 60∘​ + 60∘​ + 120∘​ = 240∘​ =>y + 2y = 120∘​ => y=40∘​ Hence, x=2y=2×40 ∴x=80

Consider the figure:

If BC = AC, x = 2y, and angle ∠ACB = 60^o, then find the value of ∠x & ∠y (in degrees).