Consider the following-1- tan - 6 2- tan 3 - 4 3- tan 5 - 4 4- tan 2 - 3 What is the correct order-

The correct option is D 4 Now,1. tan( π #160; 6 )= 1 √( 3 ) #160; 2. tan( 3π #160; 4 )= 1 3. tan( 5π #160; 4 )=1 4. tan( 2π #16 ...

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Standard X

Mathematics

Standard Values of Trigonometric Ratios

Consider the ...

Question

Consider the following:
1. $tan (\frac{π}{6})$
2. $tan (\frac{3 π}{4})$
3. $tan (\frac{5 π}{4})$
4. $tan (\frac{2 π}{3})$
What is the correct order?

1 < 4 < 2 < 3

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4 < 2 < 1 < 3

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4 < 2 < 3 < 1

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1 < 4 < 3 < 2

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Solution

The correct option is D $4 < 2 < 1 < 3$
Now,
1. $tan (\frac{π}{6}) = \frac{1}{\sqrt{3}}$

2. $tan (\frac{3 π}{4}) = - 1$

3. $tan (\frac{5 π}{4}) = 1$

4. $tan (\frac{2 π}{3}) = - \sqrt{3}$
Thus, $4 < 2 < 1 < 3$ .

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Question 22

Which of the following is an example of distributive property of multiplication over addition for rational numbers.
(a) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = [- \frac{1}{4} \times \frac{2}{3}] + [- \frac{1}{4} \times (\frac{- 4}{7})]$
(b) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = [\frac{1}{4} \times \frac{2}{3}] - (\frac{- 4}{7})$
(c) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = \frac{2}{3} + (- \frac{1}{4}) \times \frac{- 4}{7}$
(d) $- \frac{1}{4} \times {\frac{2}{3} + (\frac{- 4}{7})} = {\frac{2}{3} + (\frac{- 4}{7})} - \frac{1}{4}$

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Consider the following:1. tan(π6)2. tan(3π4)3. tan(5π4)4. tan(2π3)What is the correct order?

The correct option is D 4<2<1<3Now,1. tan(π6)=1√32. tan(3π4)=−13. tan(5π4)=14. tan(2π3)=−√3Thus, 4<2<1<3.

Consider the following:
1. $tan (\frac{π}{6})$
2. $tan (\frac{3 π}{4})$
3. $tan (\frac{5 π}{4})$
4. $tan (\frac{2 π}{3})$
What is the correct order?

The correct option is D $4 < 2 < 1 < 3$
Now,
1. $tan (\frac{π}{6}) = \frac{1}{\sqrt{3}}$

2. $tan (\frac{3 π}{4}) = - 1$

3. $tan (\frac{5 π}{4}) = 1$

4. $tan (\frac{2 π}{3}) = - \sqrt{3}$
Thus, $4 < 2 < 1 < 3$ .