Question

Consider the following addition reaction on an enantiomerically pure bromo alkene (Ref. image)

What is (are) true regarding products of the above reaction?

• A. four stereoisomers of products,each containing two chiral carbons are formed
• B. a pair of enantiomers and a meso dibromide are formed
• C. only a pair of stereoisomers of $2,3-dibromobutane$ are formed
• D. one of the product is a meso dibromide

Answer 1

Answer: (C), (D)

only a pair of stereoisomers of $2,3-dibromobutane$ are formed
one of the product is a meso dibromide

One of the product is a $meso$ dibromide

Hence options $C$ and $D$ are correct.