Consider the following anions.
When attached to $s p^{3} -$ hybridized carbon, their leaving group ability in nucleophilic substitution reaction decreases in the order :

I > I I > I I I > I V

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I > I I > I V > I I I

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I V > I > I I > I I I

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I V > I I I > I I > I

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Solution

The correct option is B $I > I I > I V > I I I$
The rate of $S_{N} 1$ reaction is largely influenced by the nature of the leaving group. The more stable the leaving group, the more easily it will be lost to favour the carbocation formation. Their decreasing order is given by
in accordance with their pKa values.

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Similar questions

s_{p^{3}}

^{3}

C F_{3} - O | | S | | O - O^{⊖}

C_{6} H_{5} - O | | S | | O - O^{⊖}

C_{6} H_{5} - O^{⊖}

C H_{3} - O | | C - O^{⊖}

s p^{3 -}

The decreasing nucleophilic order of the following compound is:

$(i) Θ C H_{3}$

$(i i) Θ N H_{2}$

$(i i i) Θ O H$

$(i v) Θ F$

H_{2} S O_{4}

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