Question

Consider the following ANSI C program:

#include<stdio.h>
int main( )
{
int arr [4] [5] ;
int i, j;
for (i = 0; i < 4; i++)
{
for (j = 0; j<5; j++)
{
arr [i] [j] = 10 * i + j;
}
}
printf("%d", *(arr[i] + 9));
return 0;
}

What is the output of the above program?

• A. 30
• B. 20
• C. 24
• D. 14

Answer 1

The correct option is C 24

int a[4] [5]
[*(a + 1) + 9]
It means skip one row and then skip 9 elements.
So, the resultant value is 24.