Consider the following balanced reaction: 2Ca(s)+O2(g)→2CaO If 60 g of Ca is placed in a reaction chamber with 32 g of O2, which will be the limiting reactant and mass of the excess reactant left?
A
Calcium; 8 g
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B
Oxygen; 16 g
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C
Calcium; 10 g
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D
Oxygen; 8 g
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Solution
The correct option is A Calcium; 8 g As per the reaction, 2 moles of Ca react with 1 mole of oxygen (2×40) g of Ca reacts with 32 g of oxygen 60 g will react with 322×40×60=24 g of oxygen Hence, Ca is the limiting reagent. The amount of excess oxygen is = 32 g - 24 g = 8 g