Question

Consider the following beam
The value of load ${}^{\prime }{w}^{\prime }$ for the loading of conjugate beam at A to be zero will be ____ kN/m.

• A. 3.41

Answer 1

The correct option is A 3.41

$M_{AB}=\frac{10\times 9^2\times 3}{{12}^2}+\frac{20\times 3^2\times 9}{{12}^2}-\frac{11}{192}\times w\times {12}^2=0$

$So,\frac{11}{192}\times 144\times w=\frac{2430+1620}{144}$

$w=3.41kN/m$