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Reviewing the Content of Mass Media

Consider the ...

Question

Consider the following C program segment:
char p[20];
char *s= "string";
int length = strlen (s) ;
for (i = 0 ; i < length; i++)
p[i] = s[length -i];
printf("%s", p);
The output of the program is

A

gnirts

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B

no output is printed

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C

gnirt

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D

string

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Solution

The correct option is B no output is printed
Because of first character is '\0' nothing will be printed

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