Consider the following calendar.

Consider any four numbers which form a square as shown below.

The difference between the product of the diagonal numbers will be equal to

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Solution

The correct option is A
7

The difference between the product of diagonal number will be equal to

$29 \times 23 - 22 \times 30$

$= 667 - 660$

$= 7$

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Consider the following calendar. Consider any four numbers which form a square as shown below. The difference between the product of the diagonal numbers will be equal to

The correct option is A 7 The difference between the product of diagonal number will be equal to 29×23−22×30 =667−660 =7

Consider the following calendar.

Consider any four numbers which form a square as shown below.

The difference between the product of the diagonal numbers will be equal to

The correct option is A
7

The difference between the product of diagonal number will be equal to

$29 \times 23 - 22 \times 30$

$= 667 - 660$

$= 7$