Consider the following carbides- ICaC2 IIBe2C IIIMgC2 IVSrC2Select the carbide which gives different product on hydrolysis than other carbides-

The correct option is B IICaC2 + 2 H2O———– gt;C2H2 + Ca(OH)2Be2C + 4 H2O ———– gt;2 Be(OH)2 + CH4MgC2 + 2 H2O —— gt;Mg(OH)2 + C2H2 SrC_2+H2O→ Sr(OH)_ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Introduction to Carbon Family

Consider the ...

Question

Consider the following carbides:
$C a C_{2} I B e_{2} C I I M g C_{2} I I I S r C_{2} I V$
Select the carbide which gives different product on hydrolysis than other carbides.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B II
CaC2 + 2 H2O----------->C2H2 + Ca(OH)2

Be2C + 4 H2O ----------->2 Be(OH)2 + CH4

MgC2 + 2 H2O ------->Mg(OH)2 + C2H2

$S r C_{2} + H 2 O \to S r (O H)_{2} + C_{2} H_{2}$

So only option B will give a different product.

Hence option B is correct.

Suggest Corrections

Consider the following carbides:CaC2IBe2CIIMgC2IIISrC2IVSelect the carbide which gives different product on hydrolysis than other carbides.

The correct option is B IICaC2 + 2 H2O----------->C2H2 + Ca(OH)2Be2C + 4 H2O ----------->2 Be(OH)2 + CH4MgC2 + 2 H2O ------->Mg(OH)2 + C2H2SrC2+H2O→Sr(OH)2+C2H2So only option B will give a different product.Hence option B is correct.

Consider the following carbides:
$C a C_{2} I B e_{2} C I I M g C_{2} I I I S r C_{2} I V$
Select the carbide which gives different product on hydrolysis than other carbides.

The correct option is B II
CaC2 + 2 H2O----------->C2H2 + Ca(OH)2

Be2C + 4 H2O ----------->2 Be(OH)2 + CH4

MgC2 + 2 H2O ------->Mg(OH)2 + C2H2

$S r C_{2} + H 2 O \to S r (O H)_{2} + C_{2} H_{2}$

So only option B will give a different product.

Hence option B is correct.